2008-03-13
19:06
用字符串模拟产生回文数,超时
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 | #include <stdio.h> #include <stdlib.h> void next_palin(char*str_of_num,int* lenth_p);/*产生下一个回文数*/ int main() { int num,lenth=1; int i,count=1; char str_of_num[30]="1"; while (scanf("%d",&num)!=EOF) { while (count<num) { next_palin(str_of_num,&lenth); count++; } for (i=0;i<lenth;i++) putchar(str_of_num[i]); putchar(’\n’); } return 0; } void next_palin(char*str_of_num,int* lenth_p)/*产生下一个回文数*/ { int i; int flag=1; for (i=0;i<*lenth_p;i++) { if (str_of_num[i]!=’9′) { flag=0; } } if (flag) { (*lenth_p)++; str_of_num[0]=str_of_num[*lenth_p-1]=’1′; for (i=1;i<*lenth_p-1;i++) { str_of_num[i]=’0′; } } else { i=*lenth_p/2; str_of_num[i]++; str_of_num[*lenth_p-1-i]=str_of_num[i]; while ((str_of_num[i]>’9′) && (i<*lenth_p-1)) { str_of_num[i]=str_of_num[*lenth_p-i-1]=’0′; str_of_num[i+1]++; str_of_num[*lenth_p-i-2]++; i++; } } } |

2008-04-19 22:56
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